Analysis of matched connection of half-wave symmetrical oscillator

Analysis of matched connection of half-wave symmetrical oscillator

Figure 1 is the cable connection diagram of the half-wave symmetrical vibrator, because the half-wave vibrator The input impedance seen from the two points AB is 73Ω, and the two vibrators have symmetry to the ground, so the impedances of the two points A and B to the ground are 73/2 = 36.5Ω. In Figure 1, the length of the 75Ω cable AC = λ / 2 + λ / 4, and the length of BC = λ / 4 (λ represents the wavelength), so AC and BC have the role of impedance transformation. The impedance of point B to ground (36.5Ω) converted to point C by cable BC is 75 * 75 / 36.5 = 154Ω; the impedance of point A (36.5Ω) converted to point C by cable AC is also 154Ω And, since AC is longer than BC by λ / 2, it also has the function of inverse conversion, thus ensuring that the signal currents at points A and B are in phase from point C. It can be seen that the impedance at point C is the parallel connection of two equivalent impedances, RC = 154/2 = 77Ω, and at this time the feeder adopts a 75Ω coaxial cable to achieve a good match.

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